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Find all services in the expression <0, 2π). 0 votes

2sin^2 x = sin x

trigonometric-equationaskedJun 18, 2013in TRIGONOMETRYby andrewScholar
you re welcome log in or register to add a comment. you re welcome log in or register to answer this question. 1 answer 0 votes

2sin^2x = sinx

2sin^2x - sinx = 0

sinx(2sinx - 1) = 0

2sinx - 1 = 0

2sinx = 1

sinx = 1/2

sinx = 30º

The solution is x = 0º,π/6, π

answeredJun 18, 2013by anonymous

sin(x) = 0 and also sin(x) = 1/2.

You are watching: Find all the solutions of the equation in the interval 0 2pi)

sin(x) = sin(0) and also sin(x) = sin(π/6).

General solution : If sin θ = sin α, then θ = nπ + (- 1)n α, whereby n is an integer.

If α = 0 climate θ = nπ.

If α = 0 then θ = nπ + (- 1)n (π/6).

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The services in the interval <0, 2π) room 0, π, π/6 and 5π/6.

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